[LUNI] Shell script question.

[Gerald Guglielmo]

Hi,
   You need quotes around the first instance of $file, and I don't think 
you need the second one because you are piping that from the echo command.

sh-3.00$ file=.foo.barxvf
sh-3.00$  echo -en "$file" | cut -d '.' -f 2
foo
sh-3.00$

Richard Reina wrote:
> Kristian,
> 
> Thanks for your reply.  However, I must still be missing something.
> 
> When I do:
> 
> #!/bin/sh
> 
> file=.foo.barxvf
> 
>  echo -en $file | cut -d '.' -f 2 $file
> #end
> 
> I get:
> 
> cut: .foo.barxvf: No such file or directory
> 
> What am I missing?
> 
> I know your example referred to the literal filename but I can't do that in my script as the suffix changes every time.  
> 
> 
> Thanks again, for the help thus far.
> 
> Richard
> 
> 
> 
> Kristian Erik Hermansen <kristian.hermansen at gmail.com> wrote: On Jan 28, 2008 10:43 AM, Richard Reina  wrote:
>> I've been playing around with inotify but my shell scripting
>> ignorance is getting in the way.
>>
>> ${file} is getting written with a dot "." and a wacky suffix like
>> ".yfEVx1" which causes the script to crash at line 5 with:
>>
>> cat .new_file.yfEVx1: no such file or directory.  How can I capture the
>> true file name as it appears (new_file) so that cat will work?
>>
>> Pardon my ignorance.  Any help would be greatly appreciated.
> 
> Pass your "wacky" file name through this filter...
> 
> cut -d '.' -f 2
> 
> Watch...
> $ echo -en '.new_file.yfEVx1' | cut -d '.' -f 2
> new_file

-- 
-Jerry->
gug at fnal.gov
Pepe's Theory of everything: "Under the right circumstances, things happen."